1650. Limited Permutation

时间限制 2000 ms   内存限制 128 MB

As to a permutation p1,p2,,pn from 1 to n, it is uncomplicated for each 1in to calculate (li,ri) meeting the condition that min(pL,pL+1,,pR)=pi if and only if liLiRri for each 1LRn.

Given the positive integers n, (li,ri) (1in), you are asked to calculate the number of possible permutations p1,p2,,pn from 1 to n, meeting the above condition.

The answer may be very large, so you only need to give the value of answer modulo 109+7.

输入数据

The input contains multiple test cases.

For each test case:

The first line contains one positive integer n, satisfying 1≤n≤106.

The second line contains n positive integers l1,l2,⋯,ln, satisfying 1≤li≤i for each 1≤i≤n.

The third line contains n positive integers r1,r2,⋯,rn, satisfying i≤ri≤n for each 1≤i≤n.

It's guaranteed that the sum of n in all test cases is not larger than 3⋅106.

Warm Tips for C/C++: input data is so large (about 38 MiB) that we recommend to use fread() for buffering friendly.
size_t fread(void *buffer, size_t size, size_t count, FILE *stream); // reads an array of count elements, each one with a size of size bytes, from the stream and stores them in the block of memory specified by buffer; the total number of elements successfully read is returned.

输出数据

For each test case, output "Case #x: y" in one line (without quotes), where x indicates the case number starting from 1 and y denotes the answer of corresponding case.

样例输入

复制
3
1 1 3
1 3 3
5
1 2 2 4 5
5 2 5 5 5 \n
 · · \n
 · · \n
 \n
 · · · · \n
 · · · · \n

样例输出

复制
Case #1: 2
Case #2: 3    ·   · \n
    ·   · \n

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2017 Multi-University Training Contest - Team 1

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