Problem D. Luba And The Ticket

时间限制 2000 ms   内存限制 256 MB

Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make the ticket lucky.

The ticket is considered lucky if the sum of first three digits equals to the sum of last three digits.

输入数据

You are given a string consisting of 6 characters (all characters are digits from 0 to 9) — this string denotes Luba's ticket. The ticket can start with the digit 0.

输出数据

Print one number — the minimum possible number of digits Luba needs to replace to make the ticket lucky.

样例

样例说明

In the first example the ticket is already lucky, so the answer is 0.

In the second example Luba can replace 4 and 5 with zeroes, and the ticket will become lucky. It's easy to see that at least two replacements are required.

In the third example Luba can replace any zero with 3. It's easy to see that at least one replacement is required.

"); $(this).append($copy); var clipboard = new Clipboard('#' + cpyId, { text: function(trigger) { return document.querySelector('#' + preId).innerText; } }); var isInput = $(this).parent().hasClass("input"); clipboard.on('success', function(e) { if (isInput) { Codeforces.showMessage("The example input has been copied into the clipboard"); } else { Codeforces.showMessage("The example output has been copied into the clipboard"); } e.clearSelection(); }); }); autosize($('.test-explanation textarea')); });

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